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Which of the following is the relation between percent strength and volume strength of hydrogen peroxide?
  • a)
    %strength = 7/56 X volume strength
  • b)
    %strength = 1/56 X volume strength
  • c)
    %strength = 17/56 X volume strength
  • d)
    %strength = 17/5 X volume strength
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Which of the following is the relation between percent strength and vo...
The relation between percentage strength and volume strength of hydrogen peroxide is given by 56 times of percent strength is equal to 17 times of volume strength, which is mathematically represented by; %strength = 17/ 56 X volume strength.
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Which of the following is the relation between percent strength and vo...
Relation between percent strength and volume strength of hydrogen peroxide

The percent strength of hydrogen peroxide is defined as the amount of hydrogen peroxide present in 100 ml of the solution. On the other hand, the volume strength of hydrogen peroxide is defined as the volume of oxygen that can be liberated from 1 ml of hydrogen peroxide solution.

Formula

The relationship between percent strength and volume strength of hydrogen peroxide can be given as:

%strength = (Volume strength x 17) / 56

Explanation

- The factor 17/56 is a constant that relates the percent strength and volume strength of hydrogen peroxide.
- This factor is derived from the fact that 1 mole of hydrogen peroxide liberates 1 mole of oxygen gas, which occupies 22.4 L at STP.
- Therefore, 1 ml of hydrogen peroxide solution with a volume strength of x releases x/22.4 moles of oxygen gas.
- The percent strength of the solution can be calculated by dividing the amount of hydrogen peroxide present in 100 ml of the solution by the total volume of the solution.
- Since 1 ml of hydrogen peroxide solution with a volume strength of x contains x/100 ml of hydrogen peroxide, the percent strength can be calculated as (x/100) x 100 = x%.
- Equating the amount of hydrogen peroxide present in 100 ml of the solution and the amount of oxygen gas released from 1 ml of the solution, we get:

x/100 = (x/22.4) x 2 x 1000

Solving for x, we get:

x = (56/17) x volume strength

Substituting this value in the expression for percent strength, we get:

%strength = (Volume strength x 17) / 56

Therefore, the correct answer is option C, %strength = 17/56 x volume strength.
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Which of the following is the relation between percent strength and volume strength of hydrogen peroxide?a)%strength = 7/56 X volume strengthb)%strength = 1/56 X volume strengthc)%strength = 17/56 X volume strengthd)%strength = 17/5 X volume strengthCorrect answer is option 'C'. Can you explain this answer?
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