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Consider the following three functions.
f1 = 10n
f2 = nlogn
f3 = n√n
Which one of the following options arranges the functions in the increasing order of asymptotic growth rate?
  • a)
    f3,f2,f1
  • b)
    f2,f1,f3
  • c)
    f1,f2,f3
  • d)
    f2,f3,f1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Consider the following three functions.f1 = 10nf2 = nlognf3 = n√...
Understanding Asymptotic Growth Rates
To compare the growth rates of the functions f1, f2, and f3, we need to analyze them as n approaches infinity.
Functions Overview
- f1 = 10n: This function grows linearly with n.
- f2 = n log n: This function grows faster than linear but slower than polynomial functions. The logarithmic factor increases the growth rate compared to f1.
- f3 = n√n: This can be rewritten as n^(3/2), a polynomial function that grows faster than both f1 and f2.
Comparing Growth Rates
- f1 vs f2: As n becomes very large, log n grows; thus, n log n grows faster than 10n. Therefore, f2 is greater than f1 for large n.
- f2 vs f3: f3 = n√n = n^(3/2) grows faster than n log n. For sufficiently large n, the polynomial term dominates the logarithmic term, making f3 greater than f2.
- f1 vs f3: Since f3 is n^(3/2) and f1 is linear, f3 will always grow faster than f1 as n increases.
Conclusion
Arranging the functions in increasing order of growth rates, we have:
- f2 (n log n)
- f3 (n√n)
- f1 (10n)
Thus, the correct order is f2, f3, f1, which corresponds to option 'D'.
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Community Answer
Consider the following three functions.f1 = 10nf2 = nlognf3 = n√...
On comparing power of these given functions : f1 has n in power. f2 has logn in power. f3 has √n in power. Hence, f2, f3, f1 is in increasing order. Note that you can take the log of each function then compare.
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