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The angle of dip at a certain place on Earth is 30o and the magnitude of Earth’s horizontal component of magnetic field is 0.35 G. Find the magnetic field at that place on Earth.
  • a)
    0.35 G
  • b)
    0.40 G
  • c)
    0.45 G
  • d)
    0.50 G
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The angle of dip at a certain place on Earth is 30oand the magnitude o...
Given: Horizontal component (H) = 0.35 G; Angle of dip (δ) = 30o
Required equation ➔ cosδ= H/B

Therefore, the magnitude of the magnetic field at that place is 0.40 G.
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Most Upvoted Answer
The angle of dip at a certain place on Earth is 30oand the magnitude o...
's magnetic field at that place is 50 microtesla. What is the horizontal component of the magnetic field at that place?

The horizontal component of the magnetic field can be found using the formula:

Bh = B * cos(dip angle)

where Bh is the horizontal component, B is the magnitude of the magnetic field, and dip angle is the angle of dip.

Plugging in the given values, we get:

Bh = 50 microtesla * cos(30o) = 43.3 microtesla

Therefore, the horizontal component of the magnetic field at that place is 43.3 microtesla.
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Community Answer
The angle of dip at a certain place on Earth is 30oand the magnitude o...
Given: Horizontal component (H) = 0.35 G; Angle of dip (δ) = 30o
Required equation ➔ cosδ= H/B

Therefore, the magnitude of the magnetic field at that place is 0.40 G.
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The angle of dip at a certain place on Earth is 30oand the magnitude of Earth’s horizontal component of magnetic field is 0.35 G. Find the magnetic field at that place on Earth.a)0.35 Gb)0.40 Gc)0.45 Gd)0.50 GCorrect answer is option 'B'. Can you explain this answer?
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