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A circuit contains two inductors of 6.0 mH inductance in parallel placed in series with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one inductor of equivalent inductance. Assuming inductors combine in series and parallel the same way resistors do, what inductance should he use?
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A circuit contains two inductors of 6.0 mH inductance in parallel plac...
Calculating the equivalent inductance:

To find the equivalent inductance of the circuit, we need to consider the inductors in series and parallel separately.

In series:
When inductors are connected in series, the equivalent inductance is the sum of the individual inductances.
Given:
- One 6.0 mH inductor
- One 8.0 mH inductor

The total inductance in series is:
L_series = 6.0 mH + 8.0 mH
L_series = 14.0 mH

In parallel:
When inductors are connected in parallel, the equivalent inductance is given by the reciprocal of the sum of the reciprocals of the individual inductances.
Given:
- One 6.0 mH inductor

The total inductance in parallel is:
L_parallel = 1 / (1/6.0 mH + 1/6.0 mH)
L_parallel = 1 / (2/6.0 mH)
L_parallel = 1 / (1/3.0 mH)
L_parallel = 3.0 mH

Replacing the inductors:

After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one equivalent inductor.

To find the equivalent inductance, we need to consider the remaining inductor in series with the parallel combination of the two 6.0 mH inductors.

In series:
The total inductance in series remains the same as before:
L_series = 14.0 mH

In parallel:
The total inductance in parallel is modified as follows:
L_parallel = 1 / (1/6.0 mH + 1/6.0 mH)
L_parallel = 1 / (2/6.0 mH)
L_parallel = 1 / (1/3.0 mH)
L_parallel = 3.0 mH

Equivalent inductance:
To find the overall equivalent inductance, we need to add the inductance in series to the inductance in parallel:
L_equivalent = L_series + L_parallel
L_equivalent = 14.0 mH + 3.0 mH
L_equivalent = 17.0 mH

Therefore, the repairman should use an inductor with an inductance of 17.0 mH to replace the three original inductors.
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A circuit contains two inductors of 6.0 mH inductance in parallel placed in series with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one inductor of equivalent inductance. Assuming inductors combine in series and parallel the same way resistors do, what inductance should he use?
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A circuit contains two inductors of 6.0 mH inductance in parallel placed in series with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one inductor of equivalent inductance. Assuming inductors combine in series and parallel the same way resistors do, what inductance should he use? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A circuit contains two inductors of 6.0 mH inductance in parallel placed in series with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one inductor of equivalent inductance. Assuming inductors combine in series and parallel the same way resistors do, what inductance should he use? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circuit contains two inductors of 6.0 mH inductance in parallel placed in series with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repairman wants to replace all three inductors with one inductor of equivalent inductance. Assuming inductors combine in series and parallel the same way resistors do, what inductance should he use?.
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