A man employed in a company is promised a salary of 3000 every month f...
Solution:
Given, the man's salary is 3000 rupees for the first year and an increment of 1000 rupees in his monthly salary every succeeding year.
To find out how much the man earns from the company in 20 years, we need to calculate his salary for each year and then add them up.
Calculation:
First year salary = 3000 rupees
Second year salary = 3000 + 1000 = 4000 rupees
Third year salary = 4000 + 1000 = 5000 rupees
Fourth year salary = 5000 + 1000 = 6000 rupees
Fifth year salary = 6000 + 1000 = 7000 rupees
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.
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Twentieth year salary = 3000 + (1000 x 19) = 21000 rupees
So, the man's salary for 20 years can be calculated as follows:
Total salary = 3000 + 4000 + 5000 + 6000 + 7000 + ... + 21000
This is an arithmetic progression with first term (a) = 3000, common difference (d) = 1000 and number of terms (n) = 20.
Using the formula for sum of an arithmetic progression, we have:
Total salary = (n/2) x [2a + (n-1)d]
= (20/2) x [2 x 3000 + (20-1) x 1000]
= 10 x [6000 + 19,000]
= 250,000 rupees
Therefore, the man earns 250,000 rupees from the company in 20 years.
A man employed in a company is promised a salary of 3000 every month f...
A=3000*12=36000, d=1000*12=12000
, S20=20/2(36000*2+19*12000) = Rs.30,00,000
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