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Consider the following C-function:double foo (int n){ int i; double sum; if (n = = 0) return 1.0; else { sum = 0.0; for (i = 0; i < n; i++) sum += foo (i); return sum; }}Suppose we modify the above function foo() and store the values of foo (i), 0 < = i < n, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:a)O(1)b)O(n)c)O(n!)d)O(nn)Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following C-function:double foo (int n){ int i; double sum; if (n = = 0) return 1.0; else { sum = 0.0; for (i = 0; i < n; i++) sum += foo (i); return sum; }}Suppose we modify the above function foo() and store the values of foo (i), 0 < = i < n, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:a)O(1)b)O(n)c)O(n!)d)O(nn)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following C-function:double foo (int n){ int i; double sum; if (n = = 0) return 1.0; else { sum = 0.0; for (i = 0; i < n; i++) sum += foo (i); return sum; }}Suppose we modify the above function foo() and store the values of foo (i), 0 < = i < n, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:a)O(1)b)O(n)c)O(n!)d)O(nn)Correct answer is option 'B'. Can you explain this answer?.

Solutions for Consider the following C-function:double foo (int n){ int i; double sum; if (n = = 0) return 1.0; else { sum = 0.0; for (i = 0; i < n; i++) sum += foo (i); return sum; }}Suppose we modify the above function foo() and store the values of foo (i), 0 < = i < n, as and when they are computed. With this modification, the time complexity for function foo() is significantly reduced. The space complexity of the modified function would be:a)O(1)b)O(n)c)O(n!)d)O(nn)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.

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