A single plate clutch is designed to transmit 10 kW power at angular v...
Problem Statement
A single plate clutch is designed to transmit 10 kW power at angular velocity of 200 rad/s, the mass moment of inertia of input shaft and that of output shaft are 0.1 kg-m² and 0.4 kg-m² respectively. What will be the time required to bring the output shaft to the rated speed from rest?
Solution
Given parameters:
- Power (P) = 10 kW
- Angular velocity (ω) = 200 rad/s
- Mass moment of inertia of input shaft (J₁) = 0.1 kg-m²
- Mass moment of inertia of output shaft (J₂) = 0.4 kg-m²
Calculation of Torque
The torque required to accelerate the output shaft from rest can be calculated as:
Torque (T) = Power (P) / Angular velocity (ω)
Substituting the given values:
T = 10,000 / 200 = 50 N-m
Calculation of Angular Acceleration
The angular acceleration of the output shaft can be calculated as:
Angular acceleration (α) = Torque (T) / Mass moment of inertia (J₂)
Substituting the given values:
α = 50 / 0.4 = 125 rad/s²
Calculation of Time
The time required to bring the output shaft to the rated speed from rest can be calculated using the following kinematic equation:
ω = ω0 + αt
where,
- ω = final angular velocity = 200 rad/s
- ω0 = initial angular velocity = 0 rad/s
- α = angular acceleration = 125 rad/s²
- t = time
Substituting the given values:
200 = 0 + 125t
t = 1.6 s
Conclusion
The time required to bring the output shaft to the rated speed from rest is 1.6 seconds.