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A single plate clutch is designed to transmit 10 kW power at angular velocity of 200 rad/s, the mass moment of inertia of input shaft and that of output shaft are 0.1 kg-m² and 0.4 kg-m² respectively. What will be the time required to bring the output shaft to the rated speed from rest?
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A single plate clutch is designed to transmit 10 kW power at angular v...
Given data:

- Power transmitted (P) = 10 kW
- Angular velocity (ω) = 200 rad/s
- Mass moment of inertia of input shaft (Jinput) = 0.1 kg-m²
- Mass moment of inertia of output shaft (Joutput) = 0.4 kg-m²

Calculating torque:

The power transmitted by the clutch can be calculated using the equation:

P = T * ω

Where T is the torque and ω is the angular velocity.

Rearranging the equation, we get:

T = P / ω

Plugging in the values, we have:

T = 10,000 / 200 = 50 Nm

Calculating angular acceleration:

The torque can be related to the angular acceleration (α) using the equation:

T = J * α

Where J is the moment of inertia and α is the angular acceleration.

Rearranging the equation, we get:

α = T / J

For the output shaft, the angular acceleration can be calculated as:

αoutput = T / Joutput = 50 / 0.4 = 125 rad/s²

Calculating time:

The angular velocity of the output shaft can be related to the angular acceleration and time (t) using the equation:

ω = α * t

Rearranging the equation, we get:

t = ω / α

For the output shaft, the time required to reach the rated speed from rest can be calculated as:

toutput = ω / αoutput = 200 / 125 = 1.6 s

Conclusion:

The time required to bring the output shaft to the rated speed from rest is 1.6 seconds.
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A single plate clutch is designed to transmit 10 kW power at angular velocity of 200 rad/s, the mass moment of inertia of input shaft and that of output shaft are 0.1 kg-m² and 0.4 kg-m² respectively. What will be the time required to bring the output shaft to the rated speed from rest?
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