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If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow?
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If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, ...
Calculation of Reynolds number and type of flow
Reynolds number is a dimensionless quantity used to determine the nature of fluid flow. It is defined as the ratio of inertial forces to viscous forces. It helps in predicting the type of flow, whether it is laminar or turbulent.
Formula for Reynolds number
Re = (ρ*v*d)/μ
where,
ρ = density of fluid
v = velocity of fluid
d = diameter of the pipe
μ = dynamic viscosity of fluid
Given data
Velocity (v) = 5 m/s
Density (ρ) = 1000 kg/m3
Diameter (d) = 400 µm = 0.0004 m
Dynamic viscosity (μ) = 0.89 Ns/m2
Substituting the given values in the Reynolds number formula
Re = (ρ*v*d)/μ
Re = (1000*5*0.0004)/0.89
Re = 2.247
Interpretation of Reynolds number
The value of Reynolds number (Re) is less than 2300. Therefore, the flow is said to be laminar. When the Reynolds number is less than 2300, the flow is smooth and the fluid particles move in parallel layers without any mixing.
Conclusion
Given the velocity, density, diameter, and dynamic viscosity of the fluid, the Reynolds number is calculated to be 2.247. Since the value of Reynolds number is less than 2300, the flow is said to be laminar.
Reynolds number is a dimensionless quantity used to determine the nature of fluid flow. It is defined as the ratio of inertial forces to viscous forces. It helps in predicting the type of flow, whether it is laminar or turbulent.
Formula for Reynolds number
Re = (ρ*v*d)/μ
where,
ρ = density of fluid
v = velocity of fluid
d = diameter of the pipe
μ = dynamic viscosity of fluid
Given data
Velocity (v) = 5 m/s
Density (ρ) = 1000 kg/m3
Diameter (d) = 400 µm = 0.0004 m
Dynamic viscosity (μ) = 0.89 Ns/m2
Substituting the given values in the Reynolds number formula
Re = (ρ*v*d)/μ
Re = (1000*5*0.0004)/0.89
Re = 2.247
Interpretation of Reynolds number
The value of Reynolds number (Re) is less than 2300. Therefore, the flow is said to be laminar. When the Reynolds number is less than 2300, the flow is smooth and the fluid particles move in parallel layers without any mixing.
Conclusion
Given the velocity, density, diameter, and dynamic viscosity of the fluid, the Reynolds number is calculated to be 2.247. Since the value of Reynolds number is less than 2300, the flow is said to be laminar.
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If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow?
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If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow?.
If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If given data velocity = 5m/s ,density =1000 kg/m3 ,diameter =400 my, dynamic viscosity =0.89 Ns/m2 find Reynolds number and type of flow?.
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