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A pile of 0.50 m diameter and length 10 m is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion = 60 kN/m2 and the angle in internal friction = 0. The skin friction capacity (kN) of the pile for an adhesion factor of 0.6?
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A pile of 0.50 m diameter and length 10 m is embedded in a deposit of ...
Calculating Skin Friction Capacity of Pile in Clay Deposit


Given Parameters:

  • Diameter of Pile (D) = 0.50 m

  • Length of Pile (L) = 10 m

  • Cohesion of Clay (c) = 60 kN/m2

  • Angle of Internal Friction of Clay (ϕ) = 0

  • Adhesion Factor (α) = 0.6



Calculating Skin Friction Capacity:
The skin friction capacity of the pile in the clay deposit is given by the following equation:
$$Q_s = \alpha \times c \times A_s$$
where Qs is the skin friction capacity, α is the adhesion factor, c is the cohesion of the clay, and As is the surface area of the pile in contact with the clay.

To calculate the surface area of the pile, we need to first calculate the circumference of the pile:
$$C = \pi \times D = 3.14 \times 0.50 = 1.57 m$$

The surface area of the pile in contact with the clay is then given by:
$$A_s = C \times L = 1.57 \times 10 = 15.7 m^2$$

Substituting the values in the skin friction capacity equation, we get:
$$Q_s = 0.6 \times 60 \times 15.7 = 566.4 kN$$

Therefore, the skin friction capacity of the pile in the clay deposit is 566.4 kN.
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A pile of 0.50 m diameter and length 10 m is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion = 60 kN/m2 and the angle in internal friction = 0. The skin friction capacity (kN) of the pile for an adhesion factor of 0.6?
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A pile of 0.50 m diameter and length 10 m is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion = 60 kN/m2 and the angle in internal friction = 0. The skin friction capacity (kN) of the pile for an adhesion factor of 0.6? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A pile of 0.50 m diameter and length 10 m is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion = 60 kN/m2 and the angle in internal friction = 0. The skin friction capacity (kN) of the pile for an adhesion factor of 0.6? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pile of 0.50 m diameter and length 10 m is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion = 60 kN/m2 and the angle in internal friction = 0. The skin friction capacity (kN) of the pile for an adhesion factor of 0.6?.
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