**Given information:**
- Initial velocity (u) = 3 m/s due east
- Final velocity (v) = 3 m/s due north
- Total time of travel (t) = 6 s

**To find:**
Acceleration (a) of the body

**Solution:**

To find the acceleration of the body, we can use the formula:

a = (v - u) / t

where:
- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time taken

**Step 1: Decompose the velocities into their components**

Since the body first moves with a velocity of 3 m/s due east and then turns due north, we need to decompose the velocities into their east and north components.

Initial velocity (u):
- East component (uᵉ) = 3 m/s
- North component (uⁿ) = 0 m/s (as the body initially moves only east)

Final velocity (v):
- East component (vᵉ) = 0 m/s (as the body turns due north)
- North component (vⁿ) = 3 m/s

**Step 2: Find the change in velocity**

The change in velocity (∆v) can be found by subtracting the initial velocity from the final velocity in each component.

Change in east component (∆vᵉ) = vᵉ - uᵉ = 0 - 3 = -3 m/s
Change in north component (∆vⁿ) = vⁿ - uⁿ = 3 - 0 = 3 m/s

**Step 3: Find the acceleration**

Using the formula a = ∆v / t, we can calculate the acceleration for each component.

Acceleration in east component (aᵉ) = ∆vᵉ / t = -3 / 6 = -0.5 m/s²
Acceleration in north component (aⁿ) = ∆vⁿ / t = 3 / 6 = 0.5 m/s²

**Step 4: Combine the components to find the overall acceleration**

To find the overall acceleration (a), we can use the Pythagorean theorem as follows:

a = √(aᵉ² + aⁿ²)

a = √((-0.5)² + (0.5)²)
a = √(0.25 + 0.25)
a = √0.5
a ≈ 0.71 m/s²

Therefore, the acceleration of the body is approximately 0.71 m/s².