The given problem can be solved using the equations of motion. Let's consider the motion of the body in two parts - the motion due east and the motion due north.


Initial velocity, u = 0 m/s (the body starts from rest)
Final velocity, v = 3 m/s
Distance covered, s = ?
Time taken, t = ?

We can use the equation v = u + at, where a is the acceleration.

Substituting the values, we get:

3 = 0 + a * t
a = 3/t


Initial velocity, u = 3 m/s (the body is already moving with a velocity of 3 m/s due east)
Final velocity, v = 3 m/s (the body continues to move with the same velocity due north)
Distance covered, s = ?
Time taken, t = ?

Since the body is moving with a constant velocity, the acceleration is zero.


Total time of travel, T = 6 s

The time taken for the motion due east and the motion due north is the same. Therefore, the time taken for each part of the motion is:

t = T/2 = 3 s


Using the equation s = ut + 1/2 at^2, we can find the distance covered by the body in each part of the motion.

For the motion due east:

s = 0 * 3 + 1/2 * a * 3^2
s = 4.5a

For the motion due north:

s = 3 * 3 + 1/2 * 0 * 3^2
s = 9

The total distance covered by the body is the sum of the distance covered in each part of the motion:

s = 4.5a + 9

Substituting the value of t, we get:

s = 4.5a + 9
solving for a we get
a = (s - 9)/4.5
a = (4.5a + 9 - 9)/4.5

a = 3/3
a = 1 m/s^2

Therefore, the acceleration of the body is 1 m/s^2.

You can do it by vector approach, as east as a x axis and north as y axis. velocity component in east as 3i^ and in north 3j^ and find the resultant velocity divide it by time you will got the acceleration