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A counting semaphore was initialized to 10. Then 6 P (wait) operations and 4 V (signal) operations were completed on this semaphore. The resulting value of the semaphore is
- a)0
- b)8
- c)10
- d)12
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A counting semaphore was initialized to 10. Then 6 P (wait) operations...
Initially we have semaphore value = 10 Now we have to perform 6 p operation means when we perform one p operation it decreases the semaphore values to one. So after performing 6 p operation we get, semaphore values = 10 - 6 = 4 and now we have to perform 4 v operation means when we perform one V operation it increases the semaphore values to one. So after performing 4 v operation we get, semaphore values = 4 + 4 = 8. Option (B) is correct.
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A counting semaphore was initialized to 10. Then 6 P (wait) operations...
Explanation:
A counting semaphore is a synchronization primitive that allows threads to wait until it is safe to access a shared resource. It maintains a count of the number of available resources.
In this case, the counting semaphore was initialized to 10. This means that there are 10 available resources initially.
P (wait) operation:
The P (wait) operation decrements the count of available resources in the semaphore. If the count becomes negative, the thread calling P (wait) is blocked and put into a waiting state until a V (signal) operation increments the count.
In this case, 6 P (wait) operations were completed on the semaphore. This means that the count of available resources was decremented by 6.
V (signal) operation:
The V (signal) operation increments the count of available resources in the semaphore. If there are threads waiting for resources, one of them is unblocked and allowed to proceed.
In this case, 4 V (signal) operations were completed on the semaphore. This means that the count of available resources was incremented by 4.
Resulting value:
To calculate the resulting value of the semaphore, we start with the initial count of available resources (10) and subtract the number of P (wait) operations (6) and add the number of V (signal) operations (4).
Initial count: 10
P (wait) operations: -6
V (signal) operations: +4
Resulting value = 10 - 6 + 4 = 8
Therefore, the resulting value of the semaphore is 8. Option B is the correct answer.
A counting semaphore is a synchronization primitive that allows threads to wait until it is safe to access a shared resource. It maintains a count of the number of available resources.
In this case, the counting semaphore was initialized to 10. This means that there are 10 available resources initially.
P (wait) operation:
The P (wait) operation decrements the count of available resources in the semaphore. If the count becomes negative, the thread calling P (wait) is blocked and put into a waiting state until a V (signal) operation increments the count.
In this case, 6 P (wait) operations were completed on the semaphore. This means that the count of available resources was decremented by 6.
V (signal) operation:
The V (signal) operation increments the count of available resources in the semaphore. If there are threads waiting for resources, one of them is unblocked and allowed to proceed.
In this case, 4 V (signal) operations were completed on the semaphore. This means that the count of available resources was incremented by 4.
Resulting value:
To calculate the resulting value of the semaphore, we start with the initial count of available resources (10) and subtract the number of P (wait) operations (6) and add the number of V (signal) operations (4).
Initial count: 10
P (wait) operations: -6
V (signal) operations: +4
Resulting value = 10 - 6 + 4 = 8
Therefore, the resulting value of the semaphore is 8. Option B is the correct answer.
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