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Suppose there are four processes in execution with 12 instances of a Resource R in a system. The maximum need of each process and current allocation are given below:
With reference to current allocation, is system safe ? If so, what is the safe sequence ?
  • a)
    No
  • b)
    Yes, P1P2P3P4
  • c)
    Yes, P4P3P1P2
  • d)
    Yes, P2P1P3P4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Suppose there are four processes in execution with 12 instances of a R...
Current allocation of P1P2P3P4 are 3, 4, 2, 1 which is 10 in total. We have 12 total no of resources and out of them 10 are allocated so, we have only 2 resources. There is 5, 5, 3, 2 resources are needed for P1P2P3P4 respectively. So, P4 will run first and free 3 resources after execution. Which are sufficient for P3 So it will execute and do free 5 resources. Now P1 and P2 both require 5 resources each So we can execute any of them first but we will give priority to P1. The execution order will be P4P3P1P2.
SO, option (C) is correct.
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Most Upvoted Answer
Suppose there are four processes in execution with 12 instances of a R...
Current allocation of P1P2P3P4 are 3, 4, 2, 1 which is 10 in total. We have 12 total no of resources and out of them 10 are allocated so, we have only 2 resources. There is 5, 5, 3, 2 resources are needed for P1P2P3P4 respectively. So, P4 will run first and free 3 resources after execution. Which are sufficient for P3 So it will execute and do free 5 resources. Now P1 and P2 both require 5 resources each So we can execute any of them first but we will give priority to P1. The execution order will be P4P3P1P2.
SO, option (C) is correct.
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