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The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is?
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The tube of an inclined tube manometer has its upper end open to air a...
Problem Statement:
The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? Explain in details.
Solution:
Given parameters are:
- Slope of tube = 1 in 4
- Specific gravity of manometer liquid = 0.72
- Movement of meniscus in the tube = 8 cm
Calculations:
The diameter of the cylinder connected to the tube is 4 times the diameter of the tube. Hence, the area of the cylinder is 16 times the area of the tube.
Let's assume the height of the manometer liquid above the tube to be h1 and the height of the liquid in the cylinder to be h2.
The pressure difference between the two points is given by:
ΔP = (ρgh1) - (ρgh2)
Where,
ρ = specific gravity of manometer liquid
g = acceleration due to gravity
Let's calculate the values of h1 and h2:
h1 = 8 cm (given)
h2 = (h1 x 4) = 32 cm
Substituting the values in the pressure difference equation:
ΔP = (0.72 x 9.81 x 8/100) - (0.72 x 9.81 x 32/100)
ΔP = -0.1906 N/m²
The negative sign indicates that the pressure above the liquid in the cylinder is less than the pressure above the liquid in the tube.
Therefore, the change in gas pressure, in height of water column, is 0.1906 m (or 19.06 cm) of water column.
Conclusion:
The change in gas pressure, in height of water column, is 0.1906 m (or 19.06 cm) of water column.
The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? Explain in details.
Solution:
Given parameters are:
- Slope of tube = 1 in 4
- Specific gravity of manometer liquid = 0.72
- Movement of meniscus in the tube = 8 cm
Calculations:
The diameter of the cylinder connected to the tube is 4 times the diameter of the tube. Hence, the area of the cylinder is 16 times the area of the tube.
Let's assume the height of the manometer liquid above the tube to be h1 and the height of the liquid in the cylinder to be h2.
The pressure difference between the two points is given by:
ΔP = (ρgh1) - (ρgh2)
Where,
ρ = specific gravity of manometer liquid
g = acceleration due to gravity
Let's calculate the values of h1 and h2:
h1 = 8 cm (given)
h2 = (h1 x 4) = 32 cm
Substituting the values in the pressure difference equation:
ΔP = (0.72 x 9.81 x 8/100) - (0.72 x 9.81 x 32/100)
ΔP = -0.1906 N/m²
The negative sign indicates that the pressure above the liquid in the cylinder is less than the pressure above the liquid in the tube.
Therefore, the change in gas pressure, in height of water column, is 0.1906 m (or 19.06 cm) of water column.
Conclusion:
The change in gas pressure, in height of water column, is 0.1906 m (or 19.06 cm) of water column.
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The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is?
Question Description
The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is?.
The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is?.
Solutions for The tube of an inclined tube manometer has its upper end open to air and the lower end connected to a vertical cylinder through having a diameter 4 times that of the tube. The slope of the tube is 1 in 4 and specific gravity of manometer liquid is 0.72. The space above the liquid in the through is connected to a gas chamber. When the movement of meniscus in the tube is 8 cm, change in gas pressure, in height of water column, is? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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