The coefficient of x4 in the expansion of (1+x+x2+x3)11 isa)900b)909c)...
Given, (1+x+x^2+x^3)^11.
To find the coefficient of x^4, we need to find the number of ways in which x^4 can be obtained by multiplying the terms in the expansion.
Let's consider the powers of x that can be obtained by multiplying the terms in the expansion:
0 (when none of the terms are multiplied)
1 (when one of the terms is multiplied)
2 (when two of the terms are multiplied)
3 (when three of the terms are multiplied)
4 (when four of the terms are multiplied)
We need to find the number of ways in which we can get a power of x equal to 4.
The maximum power of x in each term is 3. Therefore, we can only get a power of 4 by multiplying one term with power 1 and another term with power 3.
The number of ways in which we can choose one term with power 1 and another term with power 3 is:
11C1 * 10C1 = 110
We need to multiply this by the coefficient of the term (x^1 * x^3) in the expansion of (1+x+x^2+x^3)^11.
The coefficient of the term (x^1 * x^3) is the same as the coefficient of x^2 in the expansion of (1+x+x^2+x^3)^11.
To find the coefficient of x^2, we can use the multinomial theorem:
The coefficient of x^2 in the expansion of (1+x+x^2+x^3)^11 is:
(11+2-1)C(2,2,7,0) = 12C2 = 66
Therefore, the coefficient of x^4 is:
110 * 66 = 7260
But we need to divide this by 4! (4 factorial) to get the coefficient of x^4:
7260/24 = 303
Therefore, the coefficient of x^4 in the expansion of (1+x+x^2+x^3)^11 is 303, which is option D.