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Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq) C105(aq) is 10 x 10 at a temperature at which RT-2500 Jmol. Gibbs free energy change (AG)?
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Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq)...
The equilibrium constant for a chemical reaction is a measure of the extent to which the reactants are converted into products at equilibrium. It is denoted by the symbol K and is determined by the concentrations of the reactants and products.

In this case, we have the following equilibrium: 3C10 (aq) + 2C1 (aq) ⇌ C105(aq). The equilibrium constant for this reaction is given as 10 x 10.

To calculate the Gibbs free energy change (ΔG) for this reaction, we can use the equation ΔG = -RTlnK, where R is the gas constant and T is the temperature in Kelvin.

Given that RT = 2500 J/mol and the equilibrium constant (K) is 10 x 10, we can substitute these values into the equation to find the value of ΔG.

Calculating the Gibbs free energy change (ΔG):

ΔG = -RTlnK
ΔG = -(2500 J/mol)(ln(10 x 10))

Simplifying the equation:

ΔG = -(2500 J/mol)(ln(10^2))
ΔG = -(2500 J/mol)(2ln10)
ΔG = -5000 J/mol(ln10)

Now, we can calculate the value of ln10 using a calculator:

ln10 ≈ 2.3026

Substituting this value back into the equation:

ΔG = -5000 J/mol(2.3026)
ΔG ≈ -11513 J/mol

Therefore, the Gibbs free energy change (ΔG) for this reaction is approximately -11513 J/mol.

Explanation:

- The equilibrium constant (K) is a measure of the extent to which the reactants are converted into products at equilibrium.
- The Gibbs free energy change (ΔG) is a measure of the spontaneity of a reaction. A negative ΔG indicates that the reaction is spontaneous.
- The equation ΔG = -RTlnK relates the Gibbs free energy change to the equilibrium constant and temperature.
- By substituting the given values into the equation, we can calculate the value of ΔG.
- The negative value of ΔG (-11513 J/mol) indicates that the reaction is spontaneous at the given temperature.
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Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq) C105(aq) is 10 x 10 at a temperature at which RT-2500 Jmol. Gibbs free energy change (AG)?
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Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq) C105(aq) is 10 x 10 at a temperature at which RT-2500 Jmol. Gibbs free energy change (AG)? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq) C105(aq) is 10 x 10 at a temperature at which RT-2500 Jmol. Gibbs free energy change (AG)? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equilibrium constant for the following equilibrium, 3C10 (aq) 2C1 (aq) C105(aq) is 10 x 10 at a temperature at which RT-2500 Jmol. Gibbs free energy change (AG)?.
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