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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    5
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let E1 and E2 be two entities in an E/R diagram with simple single-val...
The answer is B, i.e minimum 3 tables. Strong entities E1 and E2 are represented as separate tables. In addition to that many-to-many relationships(R2) must be converted as seperate table by having primary keys of E1 and E2 as foreign keys. One-to-many relaionship (R1) must be transferred to 'many' side table(i.e. E2) by having primary key of one side(E1) as foreign key( this way we need not to make a seperate table for R1). Let relation schema be E1(a1,a2) and E2( b1,b2). Relation E1( a1 is the key)
a1 a2
-------
1 3
2 4
3 4
Relation E2( b1 is the key, a1 is the foreign key, hence R1(one-many) relationship set satisfy here )
b1 b2 a1
-----------
7 4 2
8 7 2
9 7 3
Relation R2 ( {a1, b1} combined is the key here , representing many-many relationship R2 )
a1 b1
--------
1 7
1 8
2 9
3 9
Hence we will have minimum of 3 tables.
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Most Upvoted Answer
Let E1 and E2 be two entities in an E/R diagram with simple single-val...
Answer:
To represent the given situation in the relational model, we need to create tables for entities and relationships. Let's break down the requirements and see how many tables are needed.

Entities:
- E1: This entity represents one side of the one-to-many relationship. We need a table to store the attributes of E1.
- E2: This entity represents the other side of both relationships. We also need a table to store the attributes of E2.

Relationships:
- R1: This relationship is a one-to-many relationship between E1 and E2. Since R1 does not have any attributes of its own, we can represent it by adding a foreign key column in the E2 table, referencing the primary key of E1.
- R2: This relationship is a many-to-many relationship between E1 and E2. Since R2 does not have any attributes of its own, we need to create a separate table to represent this relationship. This table will have two foreign key columns, one referencing the primary key of E1 and the other referencing the primary key of E2.

Summary:
Based on the above analysis, we need a minimum of three tables to represent the given situation in the relational model. These tables are:
1. E1 table: to store the attributes of E1
2. E2 table: to store the attributes of E2
3. R2 table: to represent the many-to-many relationship between E1 and E2

Therefore, the correct answer is option 'B' (3 tables).
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Community Answer
Let E1 and E2 be two entities in an E/R diagram with simple single-val...
The answer is B, i.e minimum 3 tables. Strong entities E1 and E2 are represented as separate tables. In addition to that many-to-many relationships(R2) must be converted as seperate table by having primary keys of E1 and E2 as foreign keys. One-to-many relaionship (R1) must be transferred to 'many' side table(i.e. E2) by having primary key of one side(E1) as foreign key( this way we need not to make a seperate table for R1). Let relation schema be E1(a1,a2) and E2( b1,b2). Relation E1( a1 is the key)
a1 a2
-------
1 3
2 4
3 4
Relation E2( b1 is the key, a1 is the foreign key, hence R1(one-many) relationship set satisfy here )
b1 b2 a1
-----------
7 4 2
8 7 2
9 7 3
Relation R2 ( {a1, b1} combined is the key here , representing many-many relationship R2 )
a1 b1
--------
1 7
1 8
2 9
3 9
Hence we will have minimum of 3 tables.
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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?
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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
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