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PH of water sample containing 0.1008 g of H ion per litre is?
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PH of water sample containing 0.1008 g of H ion per litre is?
The pH of a water sample is a measure of the concentration of hydrogen ions (H+) in the water. The pH scale ranges from 0 to 14, with lower values indicating a higher concentration of H+ ions and higher values indicating a lower concentration of H+ ions.
To calculate the pH of a water sample containing 0.1008 g of H+ ions per litre, we can use the following formula:

pH = -log[H+]

where [H+] is the concentration of H+ ions in the water, in moles per litre.

To convert the concentration of H+ ions in the water from grams per litre to moles per litre, we can use the formula:

[H+] = 0.1008 g/L * (1 mol/1.008 g) = 0.0999 mol/L

Substituting this value into the pH formula, we get:

pH = -log(0.0999 mol/L) = -(-2.002021) = 2.002021

Therefore, the pH of the water sample is approximately 2.002021. This indicates that the water sample has a relatively low concentration of H+ ions, and is therefore slightly acidic.

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PH of water sample containing 0.1008 g of H ion per litre is?
Calculating the PH of a Water Sample

To calculate the pH of a water sample containing 0.1008 g of H+ ion per litre, we need to use the formula:

pH = -log[H+]

where [H+] is the concentration of H+ ions in moles per litre.

Converting Grams to Moles

To convert the mass of H+ ions in grams to moles, we need to use the molar mass of H+. The molar mass of H+ is 1 g/mol. Therefore, the number of moles of H+ ions in 0.1008 g is:

0.1008 g / (1 g/mol) = 0.1008 mol

Calculating the Concentration of H+ ions

The concentration of H+ ions in moles per litre can be calculated using the formula:

[H+] = moles / volume

where volume is the volume of the water sample in litres. Since the question states that the volume of the water sample is 1 litre, the concentration of H+ ions is:

[H+] = 0.1008 mol / 1 L = 0.1008 M

Calculating the pH

Using the formula pH = -log[H+], we can calculate the pH of the water sample as:

pH = -log(0.1008) = 0.9964

Therefore, the pH of the water sample containing 0.1008 g of H+ ion per litre is approximately 0.9964.

Conclusion

In conclusion, the pH of a water sample containing 0.1008 g of H+ ion per litre can be calculated by first converting the mass of H+ ions in grams to moles, then calculating the concentration of H+ ions in moles per litre, and finally using the formula pH = -log[H+].
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PH of water sample containing 0.1008 g of H ion per litre is?
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