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For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are?
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For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at wh...
Calculating Bragg Reflection for NaCl Crystal
To calculate the smallest angle at which Bragg reflection occurs for a NaCl crystal with a cell edge of a=0.563 nm, we can use the Bragg's law formula:
Bragg's Law:
2dsinθ = nλ
Where:
- d is the spacing between crystal planes
- θ is the angle of incidence
- n is the order of reflection
- λ is the wavelength of the X-ray used
Calculating d-spacing for NaCl Crystal
For a face-centered cubic (FCC) crystal like NaCl, the d-spacing between crystal planes can be calculated using the formula:
d = a / √(h^2 + k^2 + l^2)
Given that NaCl crystal structure has (hkl) indices of (200), we can calculate the d-spacing.
Plugging in values:
a = 0.563 nm
h = 2, k = 0, l = 0
Calculating d-spacing:
d = 0.563 nm / √(2^2 + 0^2 + 0^2)
d = 0.563 nm / √4
d = 0.563 nm / 2
d = 0.2815 nm
Calculating the smallest angle for Bragg reflection
Now that we have the d-spacing, we can calculate the smallest angle at which Bragg reflection occurs for the (200) set of crystal planes using Bragg's law.
Plugging in values:
d = 0.2815 nm
n = 1 (first order reflection)
λ = X-ray wavelength (given or assumed)
Calculating the angle:
2 * 0.2815 nm * sinθ = λ
By solving this equation, you can find the smallest angle at which Bragg reflection occurs for the NaCl crystal with the given set of crystal planes.
To calculate the smallest angle at which Bragg reflection occurs for a NaCl crystal with a cell edge of a=0.563 nm, we can use the Bragg's law formula:
Bragg's Law:
2dsinθ = nλ
Where:
- d is the spacing between crystal planes
- θ is the angle of incidence
- n is the order of reflection
- λ is the wavelength of the X-ray used
Calculating d-spacing for NaCl Crystal
For a face-centered cubic (FCC) crystal like NaCl, the d-spacing between crystal planes can be calculated using the formula:
d = a / √(h^2 + k^2 + l^2)
Given that NaCl crystal structure has (hkl) indices of (200), we can calculate the d-spacing.
Plugging in values:
a = 0.563 nm
h = 2, k = 0, l = 0
Calculating d-spacing:
d = 0.563 nm / √(2^2 + 0^2 + 0^2)
d = 0.563 nm / √4
d = 0.563 nm / 2
d = 0.2815 nm
Calculating the smallest angle for Bragg reflection
Now that we have the d-spacing, we can calculate the smallest angle at which Bragg reflection occurs for the (200) set of crystal planes using Bragg's law.
Plugging in values:
d = 0.2815 nm
n = 1 (first order reflection)
λ = X-ray wavelength (given or assumed)
Calculating the angle:
2 * 0.2815 nm * sinθ = λ
By solving this equation, you can find the smallest angle at which Bragg reflection occurs for the NaCl crystal with the given set of crystal planes.
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For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are?
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For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are?.
For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a nacl crystal, the cell edge a=0.563 nm. the smallest angle at which bragg reflection occurs corresponding to a set of plane wave whose indices are?.
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