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If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.?
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If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.?
Solution:

Given, the geometric mean of abcd is 3.

We need to find the geometric mean of 1/a, 1/b, 1/c, 1/d.

Formula for geometric mean:

Geometric mean = nth root of product of n terms

Geometric mean of abcd = 3

abcd = 3^4 (since there are 4 terms)

abcd = 81

Now, let's find the product of 1/a, 1/b, 1/c, 1/d.

(1/a) x (1/b) x (1/c) x (1/d) = 1 / (abcd)

= 1 / 81

Now, let's find the nth root of the product of 1/a, 1/b, 1/c, 1/d.

We know that there are 4 terms, so the nth root will be the fourth root.

Geometric mean of 1/a, 1/b, 1/c, 1/d = fourth root of (1/a) x (1/b) x (1/c) x (1/d)

= fourth root of (1/81)

= 1/3

Therefore, the geometric mean of 1/a, 1/b, 1/c, 1/d is 1/3.

Conclusion:

The geometric mean of 1/a, 1/b, 1/c, 1/d is 1/3.
Community Answer
If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.?
1/3
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If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.?
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If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If geometric mean of abcd is 3 then gm of 1/a ,1/b,1/c ,1/d will be.?.
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