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16 tunning forks are arranged in the order of increasing frequencies. Any two successive forks give 8 beats per sec when sounded together. If the frequency of the last fork is twice the first, then the frequency of the first fork is
  • a)
    120
  • b)
    160
  • c)
    180
  • d)
    220
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
16 tunning forks are arranged in the order of increasing frequencies. ...
Given Information:
16 tuning forks are arranged in the order of increasing frequencies. Any two successive forks give 8 beats per sec when sounded together. The frequency of the last fork is twice the first.

Solution:

Let's assume the frequency of the first tuning fork is x Hz.
- The frequency of the second tuning fork = x + 8 Hz (since they give 8 beats per sec)
- The frequency of the third tuning fork = x + 16 Hz
- Similarly, the frequency of the 16th tuning fork = x + 120 Hz (as there are 15 intervals of 8 Hz between the first and last tuning forks)

According to the question:
- The frequency of the last tuning fork is twice the frequency of the first tuning fork.
- Therefore, x + 120 = 2x
- Solving this equation, we get x = 120 Hz as the frequency of the first tuning fork.
Therefore, the frequency of the first tuning fork is 120 Hz. Hence, the correct answer is option 'A'.
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16 tunning forks are arranged in the order of increasing frequencies. Any two successive forks give 8 beats per sec when sounded together. If the frequency of the last fork is twice the first, then the frequency of the first fork isa)120b)160c)180d)220Correct answer is option 'A'. Can you explain this answer?
Question Description
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