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A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)?
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A ball is projected horizontally at 20m/s from a cliff of height 45m. ...
Solution:
Given,
Initial velocity, u = 20 m/s
Height of the cliff, h = 45 m
Acceleration due to gravity, g = 9.8 m/s^2
Time of flight:
The time of flight is the time taken by the ball to hit the ground. This can be found using the following formula:
h = uyt - 1/2 gt^2
Where,
y = vertical displacement = h = 45 m
t = time of flight
u = initial velocity = 20 m/s
g = acceleration due to gravity = 9.8 m/s^2
Substituting the given values in the above equation, we get:
45 = 0 - 1/2 x 9.8 x t^2
t^2 = 45/4.9
t = √(45/4.9)
t = 3 seconds (approx.)
Therefore, the time of flight is 3 seconds.
Horizontal range:
The horizontal range is the horizontal distance covered by the ball before hitting the ground. This can be found using the following formula:
R = uxt
Where,
R = horizontal range
u = initial velocity = 20 m/s
t = time of flight = 3 seconds (approx.)
x = horizontal displacement
As the ball is projected horizontally, its initial velocity in the x-direction is u = 20 m/s. Therefore, the horizontal displacement can be found by multiplying the initial velocity with the time of flight:
x = u x t
x = 20 x 3
x = 60 m
Therefore, the horizontal range is 60 m.
Conclusion:
Hence, the time of flight of the ball is 3 seconds and its horizontal range is 60 m.
Given,
Initial velocity, u = 20 m/s
Height of the cliff, h = 45 m
Acceleration due to gravity, g = 9.8 m/s^2
Time of flight:
The time of flight is the time taken by the ball to hit the ground. This can be found using the following formula:
h = uyt - 1/2 gt^2
Where,
y = vertical displacement = h = 45 m
t = time of flight
u = initial velocity = 20 m/s
g = acceleration due to gravity = 9.8 m/s^2
Substituting the given values in the above equation, we get:
45 = 0 - 1/2 x 9.8 x t^2
t^2 = 45/4.9
t = √(45/4.9)
t = 3 seconds (approx.)
Therefore, the time of flight is 3 seconds.
Horizontal range:
The horizontal range is the horizontal distance covered by the ball before hitting the ground. This can be found using the following formula:
R = uxt
Where,
R = horizontal range
u = initial velocity = 20 m/s
t = time of flight = 3 seconds (approx.)
x = horizontal displacement
As the ball is projected horizontally, its initial velocity in the x-direction is u = 20 m/s. Therefore, the horizontal displacement can be found by multiplying the initial velocity with the time of flight:
x = u x t
x = 20 x 3
x = 60 m
Therefore, the horizontal range is 60 m.
Conclusion:
Hence, the time of flight of the ball is 3 seconds and its horizontal range is 60 m.
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A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)?
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A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)?.
A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected horizontally at 20m/s from a cliff of height 45m. a) find its time of flight b) find its horizontal range R ( the horizontal displacement from the point of firing)?.
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