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By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x6 1; x2 –1?
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By actual division, find the quotient and the remainder when the first...
Polynomial Division: x6 - 1 ÷ x2 - 1
To divide the polynomial x6 - 1 by x2 - 1, we will perform long division.
- **Step 1: Division of leading terms**
Divide the leading term of the dividend by the leading term of the divisor.
x6 ÷ x2 = x4
- **Step 2: Multiply and subtract**
Multiply the divisor x2 - 1 by x4 to get x6 - x4. Subtract this from the dividend.
x6 - (x6 - x4) = x4
- **Step 3: Bring down the next term**
Bring down the next term from the dividend.
x4 - 1
- **Step 4: Division of leading terms**
Divide the leading term of the new dividend x4 by the leading term of the divisor x2.
x4 ÷ x2 = x2
- **Step 5: Multiply and subtract**
Multiply the divisor x2 - 1 by x2 to get x4 - x2. Subtract this from the new dividend.
x4 - (x4 - x2) = x2
- **Step 6: Division of leading terms**
Divide the leading term of the new dividend x2 by the leading term of the divisor x2.
x2 ÷ x2 = 1
Since the degree of the new dividend is less than the degree of the divisor, we stop the division process.
Therefore, the quotient is x4 + x2 + 1 and the remainder is 0.
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By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x6 1; x2 –1?
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