Find the probability that in a random arrangement of letter of the wo...
Out of theTetters in the word ‘UNIVERSITY’ two letters ‘I’ are alike.
∴ Number of permutations = 10!/2 …(i)
Number of words in which two ‘I’ are never together = Total number of words - Number of words in which two ‘I’ are together
∴ Required probability =
= 8/10 = ⅘.
View all questions of this test
Find the probability that in a random arrangement of letter of the wo...
Probability of two 'I's not coming together in the word "UNIVERSITY"
- The word "UNIVERSITY" has 10 letters in total.
- There are 2 'I's in the word.
Total number of arrangements
- The total number of arrangements of the letters in the word "UNIVERSITY" is 10!/(3!2!) = 30,240.
Number of arrangements where two 'I's come together
- Consider the two 'I's as a single entity.
- Now, we have 9 entities (UNVERSITY + II) to arrange, which can be done in 9!/(3!) = 30,240 ways.
Number of arrangements where two 'I's do not come together
- Subtract the arrangements where two 'I's come together from the total arrangements: 30,240 - 30,240 = 0.
Probability
- Probability of two 'I's not coming together = Number of arrangements where two 'I's do not come together / Total number of arrangements
- Probability = 0 / 30,240 = 0
- Simplifying, we get 0/1 = 0.
Therefore, the probability that in a random arrangement of the word "UNIVERSITY", two 'I's do not come together is 0, which is equivalent to 0/1 or 0%. Hence, option 'A' (4/5) is incorrect, and the correct answer is option 'A' (0).
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.