Direction: A cuboid is divided into 192 identical cubelets This is d...
As we want maximize number of cubelets with green in color only cuboid has to painted with green color on set of opposite faces of 6 x 8. Hence no. of green colored only cubelets will (6 - 2) x (8 - 4) = 4 x 6 = 24, from face. There are two such faces hence maximum total no. of only green painted cubelets will be = 24 x 2 = 48
Hence option (a)
Direction: A cuboid is divided into 192 identical cubelets This is d...
Solution:
Given that a cuboid is divided into 192 identical cubelets with minimum cuts possible. All cuts are parallel to some of the faces. The cube is painted with green color on one set of opposite faces, blue on other set of opposite faces and red on their pair of annosit faces. We need to find the maximum number of cubelets possible which are colored with green color only.
To solve this problem, we need to keep in mind the following points:
- The cuboid is divided into 192 identical cubelets.
- The cuts are parallel to some of the faces.
- The cube is painted with green color on one set of opposite faces, blue on other set of opposite faces and red on their pair of annosit faces.
Let's visualize the cuboid with the given colors:
![Cuboid visualization](https://i.imgur.com/lHn0J1M.png)
From the above figure, we can see that the green color is painted on one set of opposite faces. In order to maximize the number of cubelets with green color only, we need to make cuts parallel to the faces with green color. Let's make the cuts and see how many cubelets we get:
![Cutting the cuboid](https://i.imgur.com/vX9a7GP.png)
From the above figure, we can see that we get 48 cubelets with green color only. Therefore, the maximum number of cubelets possible which are colored with green color only is 48.
Therefore, the correct answer is option 'A' - 48.