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ABCD is a parallelogram whose diagonals intersect at O. A line through O intersects AB at P and DC at Q. Then
  • a)
    area (ΔPOA) < area (ΔQOC)
  • b)
    area (ΔPOA) > area (ΔQOC)
  • c)
    area (ΔPOA) = 2area (ΔQOC)
  • d)
    area (ΔPOA) = area (ΔQOC)
Correct answer is option 'D'. Can you explain this answer?
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ABCD is a parallelogram whose diagonals intersect at O. A line through...
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ABCD is a parallelogram whose diagonals intersect at O. A line through O intersects AB at P and DC at Q. Thena)area (ΔPOA) < area (ΔQOC)b)area (ΔPOA) > area (ΔQOC)c)area (ΔPOA) = 2area (ΔQOC)d)area (ΔPOA) = area (ΔQOC)Correct answer is option 'D'. Can you explain this answer?
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