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A series circuit has 100 resistors, each having a resistance of 1 Ω and 1 A current is flowing through this circuit. What will be the current in the circuit when these 100 resistors are connected in parallel?
  • a)
    100 A
  • b)
    1000 A
  • c)
    10000 A
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A series circuit has 100 resistors, each having a resistance of 1 Ω a...
We know that,
In parallel circuit sum of the currents through each path is equal to the total current that flows from the source.
Total resistor in the circuit = 100
The value of each resistor = 1 Ω
The current in each resistor when connected in series = 1 A
Source voltage = 1 × 100 = 100 V
The current in the circuit when these 100 resistors are connected in parallel = 100 × 100 = 10000 A
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Most Upvoted Answer
A series circuit has 100 resistors, each having a resistance of 1 Ω a...
Series Circuit
In a series circuit, the resistors are connected one after the other, so the current flowing through each resistor is the same. The total resistance in a series circuit is the sum of the individual resistances.

Calculating the total resistance in the series circuit:
The total resistance (R_total) in a series circuit is given by the formula:

R_total = R1 + R2 + R3 + ... + Rn

In this case, there are 100 resistors, each with a resistance of 1 Ω. Therefore, the total resistance can be calculated as:

R_total = 1 Ω + 1 Ω + 1 Ω + ... + 1 Ω (100 times)
R_total = 100 Ω

Calculating the current in the series circuit:
The current flowing through the circuit (I_total) in a series circuit is the same at all points. In this case, it is given as 1 A.

I_total = 1 A

Parallel Circuit
In a parallel circuit, the resistors are connected side by side, so the voltage across each resistor is the same. The total resistance in a parallel circuit is calculated differently than in a series circuit.

Calculating the total resistance in the parallel circuit:
The total resistance (R_total) in a parallel circuit is given by the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

In this case, there are 100 resistors, each with a resistance of 1 Ω. Therefore, the total resistance can be calculated as:

1/R_total = 1/1 Ω + 1/1 Ω + 1/1 Ω + ... + 1/1 Ω (100 times)
1/R_total = 1 Ω + 1 Ω + 1 Ω + ... + 1 Ω (100 times)
1/R_total = 100 Ω
R_total = 1/100 Ω

Calculating the current in the parallel circuit:
The total current flowing through the circuit (I_total) in a parallel circuit is the sum of the currents flowing through each resistor. In this case, there are 100 resistors, and each resistor has the same voltage across it.

Using Ohm's Law (V = I * R), we can calculate the current flowing through each resistor:

I_resistor = V / R_resistor
I_resistor = 1 V / 1 Ω
I_resistor = 1 A

The total current flowing through the parallel circuit is the sum of the currents flowing through each resistor:

I_total = I_resistor1 + I_resistor2 + I_resistor3 + ... + I_resistor100
I_total = 1 A + 1 A + 1 A + ... + 1 A (100 times)
I_total = 100 A

Therefore, the current in the circuit when these 100 resistors are connected in parallel is 100 A.
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A series circuit has 100 resistors, each having a resistance of 1 Ω and 1 A current is flowing through this circuit. What will be the current in the circuit when these 100 resistors are connected in parallel?a)100 Ab)1000 Ac)10000 Ad)None of theseCorrect answer is option 'C'. Can you explain this answer?
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