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The capacitance of reversed biased junction J2 in thyristor is Cj2 = 20 pf and can be assumed to be independent of the off side voltage. The limiting value of the charging current to turn on the thyristor is 16mA. What is critical value of dv/dt?
- a)600 V/us
- b)800 V/us
- c)1200 V/us
- d)1000 V/us
Correct answer is option 'B'. Can you explain this answer?
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The capacitance of reversed biased junction J2 in thyristor is Cj2 = ...
Cj2 = 20pf, IJ2 = 16mA
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Then 
= 800 V/us
= 800 V/usMost Upvoted Answer
The capacitance of reversed biased junction J2 in thyristor is Cj2 = ...
Given:
- Capacitance of reversed biased junction J2 in thyristor, Cj2 = 20 pF
- The capacitance can be assumed to be independent of the off-side voltage
- Limiting value of the charging current to turn on the thyristor, I = 16 mA
To find:
Critical value of dv/dt
Explanation:
The critical value of dv/dt is the maximum rate of change of voltage that can be applied to the thyristor without triggering it. It is an important parameter to ensure the safe operation of the device.
The charging current in a thyristor can be expressed as:
I = C * (dv/dt)
Where:
I = Charging current
C = Capacitance of the junction
dv/dt = Rate of change of voltage
Substituting the given values:
I = 16 mA
C = 20 pF
16 mA = 20 pF * (dv/dt)
Simplifying the equation:
dv/dt = (16 mA) / (20 pF)
Converting the units:
1 mA = 10^-3 A
1 pF = 10^-12 F
dv/dt = (16 * 10^-3 A) / (20 * 10^-12 F)
dv/dt = 800 V/μs
Therefore, the critical value of dv/dt is 800 V/μs. Hence, option 'B' is the correct answer.
- Capacitance of reversed biased junction J2 in thyristor, Cj2 = 20 pF
- The capacitance can be assumed to be independent of the off-side voltage
- Limiting value of the charging current to turn on the thyristor, I = 16 mA
To find:
Critical value of dv/dt
Explanation:
The critical value of dv/dt is the maximum rate of change of voltage that can be applied to the thyristor without triggering it. It is an important parameter to ensure the safe operation of the device.
The charging current in a thyristor can be expressed as:
I = C * (dv/dt)
Where:
I = Charging current
C = Capacitance of the junction
dv/dt = Rate of change of voltage
Substituting the given values:
I = 16 mA
C = 20 pF
16 mA = 20 pF * (dv/dt)
Simplifying the equation:
dv/dt = (16 mA) / (20 pF)
Converting the units:
1 mA = 10^-3 A
1 pF = 10^-12 F
dv/dt = (16 * 10^-3 A) / (20 * 10^-12 F)
dv/dt = 800 V/μs
Therefore, the critical value of dv/dt is 800 V/μs. Hence, option 'B' is the correct answer.
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The capacitance of reversed biased junction J2 in thyristor is Cj2 = 20 pf and can be assumed to be independent of the off side voltage. The limiting value of the charging current to turn on the thyristor is 16mA. What is critical value of dv/dt?a)600 V/usb)800 V/usc)1200 V/usd)1000 V/usCorrect answer is option 'B'. Can you explain this answer?
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