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If position of object change with time as x = t2 + 4t + 5, then the net displacement of the object in time interval t = 1 s to t = 4 s is?
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If position of object change with time as x = t2 + 4t + 5, then the ne...
Given: The position of the object changes with time as x = t^2 + 4t + 5.

To find: The net displacement of the object in time interval t = 1 s to t = 4 s.

Solution:
To find the displacement of the object, we need to find the distance covered by the object in the given time interval.

Step 1: Calculate the position of the object at t=1s and t=4s.
- When t=1s, x = t^2 + 4t + 5 = 1^2 + 4(1) + 5 = 10m
- When t=4s, x = t^2 + 4t + 5 = 4^2 + 4(4) + 5 = 33m

Step 2: Calculate the distance covered by the object.
- Distance covered = Final position - Initial position
- Distance covered = 33m - 10m = 23m

Step 3: Calculate the displacement of the object.
- Displacement of the object is the shortest distance between the initial and final positions of the object.
- The object moves in the positive direction, so the displacement is equal to the distance covered.
- Displacement of the object = 23m

Answer: The net displacement of the object in the time interval t=1s to t=4s is 23m.
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