Ratio of energy of electron in ground state of Hydrogen to the electron in first excited state of Be3:

The energy of an electron in an atom is quantized. The energy of an electron in an atom is given by the formula E = (-13.6/n^2) eV, where n is the principal quantum number.

Energy of electron in ground state of Hydrogen:

Hydrogen atom has only one electron. The electron in hydrogen atom is in its ground state when it is in the first energy level (n=1). Therefore, the energy of the electron in the ground state of hydrogen is given by E = (-13.6/1^2) eV = -13.6 eV.

Energy of electron in first excited state of Be3:

Be3 is a positively charged ion with 3 protons and 3 electrons. The first excited state of Be3 is when one of its electrons is in the second energy level (n=2). Therefore, the energy of the electron in the first excited state of Be3 is given by E = (-13.6/2^2) eV = -3.4 eV.

Ratio of energy:

The ratio of energy of electron in ground state of Hydrogen to the electron in first excited state of Be3 is given by:

-13.6 eV / -3.4 eV = 4

Therefore, the ratio of energy of electron in ground state of Hydrogen to the electron in first excited state of Be3 is 4.

Explanation:

The energy of an electron in an atom is quantized. The energy of an electron in an atom is given by the formula E = (-13.6/n^2) eV, where n is the principal quantum number. The energy of an electron in the ground state of hydrogen is -13.6 eV and the energy of an electron in the first excited state of Be3 is -3.4 eV. Therefore, the ratio of energy of electron in ground state of Hydrogen to the electron in first excited state of Be3 is 4.