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In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?
- a)+3.4 eV
- b)+1.51 eV
- c)–3.4 eV
- d)–1.51 eV
Correct answer is option 'B'. Can you explain this answer?
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In an inelastic collision an electron excites as hydrogen atom from it...
Minimum energy required by electron should be +1.51 eV
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In an inelastic collision an electron excites as hydrogen atom from it...
To find the minimum energy transferred by the second electron to the hydrogen atom in the M-shell state, we need to consider the energy difference between the ground state and the M-shell state of hydrogen.
The energy required to excite an electron from the ground state to the M-shell state can be calculated using the Rydberg formula:
E = -13.6 eV * (1/n^2)
where n is the principal quantum number. For the M-shell state, n = 3.
E = -13.6 eV * (1/3^2)
= -13.6 eV * (1/9)
= -1.51 eV
So, the energy required to excite the hydrogen atom to the M-shell state is 1.51 eV. Since the collision is inelastic, the second electron must transfer at least this amount of energy to ionize the hydrogen atom.
Therefore, the minimum energy transferred by the second electron to the atom in the M-state is 1.51 eV.
The correct answer is b) 1.51 eV.
The energy required to excite an electron from the ground state to the M-shell state can be calculated using the Rydberg formula:
E = -13.6 eV * (1/n^2)
where n is the principal quantum number. For the M-shell state, n = 3.
E = -13.6 eV * (1/3^2)
= -13.6 eV * (1/9)
= -1.51 eV
So, the energy required to excite the hydrogen atom to the M-shell state is 1.51 eV. Since the collision is inelastic, the second electron must transfer at least this amount of energy to ionize the hydrogen atom.
Therefore, the minimum energy transferred by the second electron to the atom in the M-state is 1.51 eV.
The correct answer is b) 1.51 eV.
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In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?a)+3.4 eVb)+1.51 eVc)–3.4 eVd)–1.51 eVCorrect answer is option 'B'. Can you explain this answer?
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In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?a)+3.4 eVb)+1.51 eVc)–3.4 eVd)–1.51 eVCorrect answer is option 'B'. Can you explain this answer? for 2024 is part of preparation. The Question and answers have been prepared according to the exam syllabus. Information about In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?a)+3.4 eVb)+1.51 eVc)–3.4 eVd)–1.51 eVCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?a)+3.4 eVb)+1.51 eVc)–3.4 eVd)–1.51 eVCorrect answer is option 'B'. Can you explain this answer?.
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