Question Description
Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer?.

Solutions for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Densities of diamond and graphite are 3.5 and 2.3 gm/mL. respectively and for C(diamond) C (graphite) ; ΔH= -1.9 kJ/mole favourable conditions for formation of diamond are a)High pressure and low temperature b)Low pressure and high temperature c)High pressure and high temperature d)Low pressure and low temperature Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.