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A man borrows 20000rs and agree to pay borrowed amount in 10 equal installments at the rate of 6% p.a find the amount of each instalment the first being paid one year after the money was borrowed?
Most Upvoted Answer
A man borrows 20000rs and agree to pay borrowed amount in 10 equal ins...
Given data:
- Principal amount (P) = 20000rs
- Number of installments (n) = 10
- Rate of interest (r) = 6% p.a
- First installment paid after 1 year

Formula used:
EMI = [P x r x (1 + r)^n] / [(1 + r)^n - 1]

Calculation:
Step 1: Calculate the interest rate per installment
Since the interest rate is given as 6% p.a, we need to find the interest rate per installment. As there are 12 months in a year, the interest rate per month will be 6/12 = 0.5%.
Therefore, the interest rate per installment = 0.5%

Step 2: Calculate the total interest payable
As the loan is for 10 installments and the first installment is paid after 1 year, the total time period for the loan will be 11 years. Therefore, the total interest payable will be:
Total interest = P x r x n
= 20000 x 0.5/100 x 10
= 10000rs

Step 3: Calculate the total amount payable
The total amount payable will be the sum of the principal and the total interest payable.
Total amount payable = P + Total interest
= 20000 + 10000
= 30000rs

Step 4: Calculate the EMI
Using the formula for EMI, we get:
EMI = [P x r x (1 + r)^n] / [(1 + r)^n - 1]
= [30000 x 0.5/100 x (1 + 0.5/100)^10] / [(1 + 0.5/100)^10 - 1]
= 3371.81rs (approx.)

Therefore, the amount of each installment will be 3371.81rs, with the first installment being paid after 1 year.
Community Answer
A man borrows 20000rs and agree to pay borrowed amount in 10 equal ins...
If this is SI , then each installment would be - 3200
and in CI, each installment would be - 3581.6
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A man borrows 20000rs and agree to pay borrowed amount in 10 equal installments at the rate of 6% p.a find the amount of each instalment the first being paid one year after the money was borrowed?
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