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At a constant volume the specific heat of a gas is 0.075 and its molecular weight is 40. The gas is:
- a)Monoatomic
- b)Diatomic
- c)Triatomic
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
At a constant volume the specific heat of a gas is 0.075 and its molec...
⇒ CV = q × m
= 0.075 × 40
= 3.0 cal
CP – Cv = R
CP = CV + R
= 3 + 2 = 5
Monoatomic gas.
Most Upvoted Answer
At a constant volume the specific heat of a gas is 0.075 and its molec...
Reasoning:
The specific heat at constant volume of a gas can provide information about the degrees of freedom of the molecules in the gas. For monoatomic gases, the specific heat at constant volume is 3/2R, for diatomic gases it is 5/2R, and for triatomic gases it is 6/2R or 3R.
Given Information:
Specific heat at constant volume (Cv) = 0.075
Molecular weight = 40
Analysis:
To determine the type of gas, we can use the equation relating specific heat at constant volume to the degrees of freedom:
Cv = (f/2)R
Where:
Cv = specific heat at constant volume
f = degrees of freedom
R = gas constant
Solution:
Given that Cv = 0.075 and molecular weight = 40, we can calculate the gas constant R using R = 8.314 J/mol-K.
Now, substituting the values of Cv and R into the equation, we get:
0.075 = (f/2) * 8.314
f = 0.075 * 2 / 8.314
f ≈ 0.018
Since the degrees of freedom (f) is approximately 0.018, which is closest to 0, the gas is considered monoatomic.
Therefore, the correct answer is option 'A' - Monoatomic.
The specific heat at constant volume of a gas can provide information about the degrees of freedom of the molecules in the gas. For monoatomic gases, the specific heat at constant volume is 3/2R, for diatomic gases it is 5/2R, and for triatomic gases it is 6/2R or 3R.
Given Information:
Specific heat at constant volume (Cv) = 0.075
Molecular weight = 40
Analysis:
To determine the type of gas, we can use the equation relating specific heat at constant volume to the degrees of freedom:
Cv = (f/2)R
Where:
Cv = specific heat at constant volume
f = degrees of freedom
R = gas constant
Solution:
Given that Cv = 0.075 and molecular weight = 40, we can calculate the gas constant R using R = 8.314 J/mol-K.
Now, substituting the values of Cv and R into the equation, we get:
0.075 = (f/2) * 8.314
f = 0.075 * 2 / 8.314
f ≈ 0.018
Since the degrees of freedom (f) is approximately 0.018, which is closest to 0, the gas is considered monoatomic.
Therefore, the correct answer is option 'A' - Monoatomic.
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At a constant volume the specific heat of a gas is 0.075 and its molecular weight is 40. The gas is:a)Monoatomicb)Diatomicc)Triatomicd)None of theseCorrect answer is option 'A'. Can you explain this answer?
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