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P and Q starting simultaneously from two different places proceed towards each other at a speed of 20 km/hour and 30 km/hour respectively. By the time they meet each other, Q has covered 36 km more than P. The distance (in k.m.) between the two places is:
  • a)
    108
  • b)
    144
  • c)
    162
  • d)
    180
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
P and Q starting simultaneously from two different places proceed tow...
Let the distance = x km
Let them meet when P travels y km.
then, Q travels in the same time x – y km
from question,
(x – y) – y = 36
x – 2y = 36 .......(i)
Also, 20 × y = 30 (x–y) [∵Time is same]
∴y/x−y−=3/2
2y = 3x – 3y
5y = 3x ........(ii)
Putting the value of y from (ii) to (i),
x−6x/5=36⇒−x/5=36⇒x=180 km
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Most Upvoted Answer
P and Q starting simultaneously from two different places proceed tow...
Given:
Speed of P = 20 km/hour
Speed of Q = 30 km/hour

Let's assume that the distance between the two places is 'D' km.

- Calculating the time taken by P and Q to meet each other:
The relative speed of P and Q = Speed of P + Speed of Q = 20 + 30 = 50 km/hour
Time taken = Distance/Speed = D/50 hours

- Calculating the distance covered by P and Q when they meet:
Distance covered by P = Speed of P * Time taken = 20 * (D/50) = (2D/5) km
Distance covered by Q = Speed of Q * Time taken = 30 * (D/50) = (3D/5) km

- Given that Q has covered 36 km more than P:
(3D/5) - (2D/5) = 36
(1D/5) = 36
D = 36 * 5 = 180 km

Therefore, the distance between the two places is 180 km. Hence, option 'D' is the correct answer.
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P and Q starting simultaneously from two different places proceed towards each other at a speed of 20 km/hour and 30 km/hour respectively. By the time they meet each other, Q has covered 36 km more than P. The distance (in k.m.) between the two places is:a)108b)144c)162d)180Correct answer is option 'D'. Can you explain this answer?
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