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The hyetograph of a storm of 6h duration is constructed with varying time intervals: at 20 minutes interval for the first one hour, at 40 minutes interval for the next 2 hours and at one hour interval for the last 3 hours. The successive ordinate of the hyetograph in mm/h are 66, 75, 54, 48, 69, 51, 38, 47 and 25. Determine the total rainfall depth produced by the storm.?
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The hyetograph of a storm of 6h duration is constructed with varying t...
Problem: Determine the total rainfall depth produced by the storm with a hyetograph of 6h duration constructed using varying time intervals.

Solution:

Step 1: Calculate the area of the trapezoids formed by each interval of the hyetograph.

- For the first hour, with 20 minutes interval:
- Area = ((1/3) x (66 + 75 + 54) x (20/60)) + ((1/2) x (54 + 48) x (20/60))
- Area = 9 + 2.8
- Area = 11.8 mm

- For the next 2 hours, with 40 minutes interval:
- Area = ((1/3) x (75 + 54 + 69) x (40/60)) + ((1/2) x (69 + 51) x (40/60))
- Area = 20 + 11.2
- Area = 31.2 mm

- For the last 3 hours, with 1 hour interval:
- Area = ((1/3) x (54 + 48 + 38) x 1) + ((1/2) x (38 + 47) x 1) + ((1/2) x (47 + 25) x 1)
- Area = 46.7 mm

Step 2: Add up the areas of the trapezoids to get the total rainfall depth produced by the storm.

- Total rainfall depth = 11.8 + 31.2 + 46.7
- Total rainfall depth = 89.7 mm

Therefore, the total rainfall depth produced by the storm is 89.7 mm.
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The hyetograph of a storm of 6h duration is constructed with varying time intervals: at 20 minutes interval for the first one hour, at 40 minutes interval for the next 2 hours and at one hour interval for the last 3 hours. The successive ordinate of the hyetograph in mm/h are 66, 75, 54, 48, 69, 51, 38, 47 and 25. Determine the total rainfall depth produced by the storm.?
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