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The kinetic energy of an object of mass 'm', moving with a velocity of 5 ms-1 is 25 J. If the velocity is increased
by three times, the kinetic energy is :
- a)100J
- b)225J
- c)400J
- d)180J
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The kinetic energy of an object of mass m, moving with a velocity of 5...
Given- K.E- 25J, velocity-5m/s
So, m will be:-
K.E=1/2mv²
25=1/2×m×(5)²
25×2/25=m
2=m
m=2kg
If velocity is increased 3 times, 5×3=15m/s,then K.E will be:-
K.E=1/2mv²
=1/2×2×(15)²
=225J, so option 'B' is correct
So, m will be:-
K.E=1/2mv²
25=1/2×m×(5)²
25×2/25=m
2=m
m=2kg
If velocity is increased 3 times, 5×3=15m/s,then K.E will be:-
K.E=1/2mv²
=1/2×2×(15)²
=225J, so option 'B' is correct
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Community Answer
The kinetic energy of an object of mass m, moving with a velocity of 5...
Given:
Mass of the object, m = ?
Velocity of the object, v = 5 m/s
Kinetic energy, KE = 25 J
To find:
The kinetic energy of the object when its velocity is increased by three times.
Formula:
The formula to calculate kinetic energy is given by:
KE = (1/2)mv^2
Step-by-step solution:
1. We know that the kinetic energy (KE) is given by the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity.
2. Substituting the given values into the formula, we have 25 = (1/2)m(5)^2.
3. Simplifying the equation, we get 25 = (1/2)25m.
4. Further simplifying, we have 25 = 12.5m.
5. Dividing both sides of the equation by 12.5, we get m = 2 kg.
6. Now, we need to find the kinetic energy when the velocity is increased by three times.
7. Let the new velocity be v'.
8. The new kinetic energy, KE', can be calculated using the formula KE' = (1/2)mv'^2.
9. Since the velocity is increased by three times, we have v' = 3v = 3 * 5 = 15 m/s.
10. Substituting the values into the formula, we have KE' = (1/2)(2)(15)^2 = 225 J.
Therefore, the kinetic energy of the object when its velocity is increased by three times is 225 J, which corresponds to option B.
Mass of the object, m = ?
Velocity of the object, v = 5 m/s
Kinetic energy, KE = 25 J
To find:
The kinetic energy of the object when its velocity is increased by three times.
Formula:
The formula to calculate kinetic energy is given by:
KE = (1/2)mv^2
Step-by-step solution:
1. We know that the kinetic energy (KE) is given by the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity.
2. Substituting the given values into the formula, we have 25 = (1/2)m(5)^2.
3. Simplifying the equation, we get 25 = (1/2)25m.
4. Further simplifying, we have 25 = 12.5m.
5. Dividing both sides of the equation by 12.5, we get m = 2 kg.
6. Now, we need to find the kinetic energy when the velocity is increased by three times.
7. Let the new velocity be v'.
8. The new kinetic energy, KE', can be calculated using the formula KE' = (1/2)mv'^2.
9. Since the velocity is increased by three times, we have v' = 3v = 3 * 5 = 15 m/s.
10. Substituting the values into the formula, we have KE' = (1/2)(2)(15)^2 = 225 J.
Therefore, the kinetic energy of the object when its velocity is increased by three times is 225 J, which corresponds to option B.
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The kinetic energy of an object of mass m, moving with a velocity of 5 ms-1is 25 J. If the velocity is increasedby three times, the kinetic energy is :a)100Jb)225Jc)400Jd)180JCorrect answer is option 'B'. Can you explain this answer?
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