Question Description
For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer?.

Solutions for For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For diffraction of light, the condition for nth secondary minimum is that path difference is equal to [Here a is the width of slit, n is the order of diffraction, λ is the wavelength of light and θ n gives the direction of nth secondary minimum ]a)a sin θn = nλb)a sin θn = (2n+1λ)c)d)Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.