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Multiply using box multiplication method.
233 × 65
  • a)
    15145
  • b)
    15115
  • c)
    15445
  • d)
    15454
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Multiply using box multiplication method.233 × 65a)15145b)15115c...
233 × 65 = 12000 + 1800 + 180 + 1000 + 150 + 15 = 15145
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Community Answer
Multiply using box multiplication method.233 × 65a)15145b)15115c...
To multiply 233 using the box multiplication method, follow these steps:

Step 1: Write the numbers in a box, with the larger number on top and the smaller number on the side.

2 3 3
× 2 3 3

Step 2: Multiply the digits in the ones place of both numbers. In this case, it is 3 × 3 = 9.

2 3 3
× 2 3 3
-------
9

Step 3: Multiply the digit in the tens place of the top number by the digit in the ones place of the bottom number. In this case, it is 3 × 3 = 9.

2 3 3
× 2 3 3
-------
9
9

Step 4: Multiply the digit in the ones place of the top number by the digit in the tens place of the bottom number. In this case, it is 3 × 2 = 6.

2 3 3
× 2 3 3
-------
9
9
+ 6

Step 5: Multiply the digit in the tens place of both numbers. In this case, it is 2 × 2 = 4.

2 3 3
× 2 3 3
-------
9
9 4
+ 6

Step 6: Add up all the partial products.

2 3 3
× 2 3 3
-------
9
9 4
+ 6 9 9
-------
= 54,689

So, 233 multiplied by 233 using the box multiplication method is equal to 54,689.
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Multiply using box multiplication method.233 × 65a)15145b)15115c)15445d)15454Correct answer is option 'A'. Can you explain this answer? for Class 4 2025 is part of Class 4 preparation. The Question and answers have been prepared according to the Class 4 exam syllabus. Information about Multiply using box multiplication method.233 × 65a)15145b)15115c)15445d)15454Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 4 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Multiply using box multiplication method.233 × 65a)15145b)15115c)15445d)15454Correct answer is option 'A'. Can you explain this answer?.
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