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In a thermodynamic process, the pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If the initial internal energy of the gas was 30 J, then the final internal energy will be
  • a)
    2 J
  • b)
    42 J
  • c)
    18 J
  • d)
    58 J
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a thermodynamic process, the pressure of a fixed mass of a gas is c...
Given ΔQ = – 20 J, W = – 8 J
Using Ist law ΔQ = ΔU + ΔW
⇒ ΔQ = – 20 + 8 = – 12 J
Uf = – 12 + 30 = 18 J
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Community Answer
In a thermodynamic process, the pressure of a fixed mass of a gas is c...
Initial Internal Energy: 30 J
Heat Released: 20 J
Work Done on the gas: 8 J

To determine the final internal energy of the gas, we need to consider the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

Where:
ΔU = Change in internal energy
Q = Heat added to the system
W = Work done by the system

Substituting the given values into the equation, we have:

ΔU = 20 J - 8 J
ΔU = 12 J

Therefore, the change in internal energy of the gas is 12 J.

To find the final internal energy, we add the change in internal energy to the initial internal energy:

Final Internal Energy = Initial Internal Energy + Change in Internal Energy
Final Internal Energy = 30 J + 12 J
Final Internal Energy = 42 J

Hence, the final internal energy of the gas is 42 J.

Therefore, the correct answer is option 'C' (18 J).
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In a thermodynamic process, the pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If the initial internal energy of the gas was 30 J, then the final internal energy will bea)2 Jb)42 Jc)18 Jd)58 JCorrect answer is option 'C'. Can you explain this answer?
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