How many times the H.C.F. of 11, 33 and 88 is their L.C.M?a)11b)24c)22...
H.C.F. of 11, 33 and 88 is 11.
L.C.M. of 11,33 and 88 is 11 × 3 × 8 = 11 × 24 = H.C.F .× 24.
How many times the H.C.F. of 11, 33 and 88 is their L.C.M?a)11b)24c)22...
Solution:
To find the H.C.F. (Highest Common Factor) and L.C.M. (Least Common Multiple) of the given numbers, we need to first find the prime factors of each number.
Prime factors of 11: 11
Prime factors of 33: 3, 11
Prime factors of 88: 2, 2, 2, 11
Finding the H.C.F.:
The H.C.F. is the highest common factor among all the given numbers. To find it, we need to take the common prime factors of the numbers with the lowest exponent.
11 is a common prime factor, and its lowest exponent is 1.
Therefore, H.C.F. = 11.
Finding the L.C.M.:
The L.C.M. is the least common multiple of the given numbers, which can be found by multiplying all the prime factors with their highest exponent.
Prime factors of 11: 11
Prime factors of 33: 3, 11
Prime factors of 88: 2, 2, 2, 11
Multiplying all the prime factors with their highest exponent:
L.C.M. = 2 x 2 x 2 x 3 x 11 = 24 x 33 = 792.
Verifying the answer:
To verify if the H.C.F. is equal to the L.C.M., we can divide the L.C.M. by the H.C.F.
L.C.M. / H.C.F. = 792 / 11 = 72.
Since the H.C.F. is equal to 11 and the L.C.M. is equal to 792, the answer is not 72.
Therefore, the correct answer is option 'B' - 24.