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Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively. Arrange the acids in increasing order of acidic strength.
  • a)
    HCOOH > CH3COOH > H2S > HCN
  • b)
    CH3COOH > HCOOH > H2S > HCN
  • c)
    H2S > HCOOH > CH3COOH > HCN
  • d)
    HCOOH > H2S > CH3COOH > HCN
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are &nda...
The heats of neutralization for CH3COOH, HCOOH, HCN, and H2S are not provided in the prompt.
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Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are &nda...
The greater the (negative value) of heat of neutralisation, the more is the strength of  the acid. Hence,
HCOOH > CH3COOH > H2S > HCN
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Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.Which of the following solutions, when mixed with 100 ml of 0.05 M NaOH, will give a neutral solution?

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.How many gram of phosphoric acid (H3PO4) would be required to neutralize 58 g of magnesium hydroxide?

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seamctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine. Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates. Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water ( = 18 g).Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule. 0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.When 5.00 g of a metal is strongly heated, 9.44 g of its oxide is obtained. The equivalent mass of the metal is

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.9.8 g of an acid on treatment with excess of an alkali forms salt along with 3.6 g of water. What is the equivalent mass of the acid?

Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer?
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Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Th e heats of neutra lisation of CH3CO OH, HCOOH, HCN and H2S are – 13.2, – 13.4, – 2.9 and – 3.8 kCal per equivalent respectively.Arrange the acids in increasing order of acidic strength.a)HCOOH > CH3COOH > H2S > HCNb)CH3COOH > HCOOH > H2S > HCNc)H2S > HCOOH > CH3COOH > HCNd)HCOOH > H2S > CH3COOH > HCNCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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