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Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer?.

Solutions for Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Hydrogen (H), deuterium (D), sin gly ionized helium (He+) and doubly ionized lithium (Li++) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelengths of emitted radiations are λ1, λ2, λ3 and λ4 respectively.Then approximately :a)λ1 = λ2 = 4 λ3 = 9λ4b)4 λ1 = 2λ2 = 2λ3 = λ4c)λ1 = 2λ2 = 2√2λ3 = 3√2λ4d)λ1 = λ2 = 2 λ3 = 3√2λ4Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.