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In order to determine the water content, 370 g of a wet sandy sample was placed in a pycnometer. The mass of the pycnometer, sand, and water full to the top of the conical cap was found to be 2148 g. The mass of pycnometer full of clean water was 1932 g. Taking G = 2.65.
What is the water content of the soil sample?
  • a)
    1.95%
  • b)
    2.75%
  • c)
    3.25%
  • d)
    6.50%
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In order to determine the water content, 370 g of a wet sandy sample ...
Concept
Where
M1 = Mass of the pycnometer
M2 = Mass of pycnometer + Oven-dried soil sample
M3 = Mass of pycnometer + Oven-dried soil sample + Water filled
M4 = Mass of pycnometer + Water filled
G = Specific Gravity of Soil
Calculation:
w = 6.5%
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Most Upvoted Answer
In order to determine the water content, 370 g of a wet sandy sample ...
Given information:
- Mass of wet sandy sample = 370 g
- Mass of pycnometer, sand, and water full to the top of the conical cap = 2148 g
- Mass of pycnometer full of clean water = 1932 g
- Value of G (specific gravity of solids) = 2.65

To determine the water content of the soil sample, we need to use the formula:

Water content = ((mass of water / mass of solids) x 100)

Where,
- Mass of water = Mass of pycnometer, sand, and water full to the top of the conical cap - Mass of pycnometer full of clean water
- Mass of solids = Mass of pycnometer, sand, and water full to the top of the conical cap - Mass of pycnometer

Calculations:
- Mass of water = 2148 g - 1932 g = 216 g
- Mass of solids = 2148 g - 370 g = 1778 g
- Specific gravity of solids (G) = 2.65

Using the formula for water content:
Water content = ((216 g / 1778 g) x 100) = 12.16%

However, this value is not correct because we have not taken into account the specific gravity of solids. We need to adjust our calculation using the following formula:

Water content = ((mass of water / (mass of solids x G)) x 100)

Calculations:
- Mass of solids (adjusted for specific gravity) = Mass of solids / G = 1778 g / 2.65 = 670.19 g
- Water content = ((216 g / (670.19 g)) x 100) = 32.23%

Therefore, the water content of the soil sample is 32.23%, which corresponds to option D (6.50% is incorrect).
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In order to determine the water content, 370 g of a wet sandy sample was placed in a pycnometer. The mass of the pycnometer, sand, and water full to the top of the conical cap was found to be 2148 g. The mass of pycnometer full of clean water was 1932 g. Taking G = 2.65.What is the water content of the soil sample?a)1.95%b)2.75%c)3.25%d)6.50%Correct answer is option 'D'. Can you explain this answer?
Question Description
In order to determine the water content, 370 g of a wet sandy sample was placed in a pycnometer. The mass of the pycnometer, sand, and water full to the top of the conical cap was found to be 2148 g. The mass of pycnometer full of clean water was 1932 g. Taking G = 2.65.What is the water content of the soil sample?a)1.95%b)2.75%c)3.25%d)6.50%Correct answer is option 'D'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about In order to determine the water content, 370 g of a wet sandy sample was placed in a pycnometer. The mass of the pycnometer, sand, and water full to the top of the conical cap was found to be 2148 g. The mass of pycnometer full of clean water was 1932 g. Taking G = 2.65.What is the water content of the soil sample?a)1.95%b)2.75%c)3.25%d)6.50%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In order to determine the water content, 370 g of a wet sandy sample was placed in a pycnometer. The mass of the pycnometer, sand, and water full to the top of the conical cap was found to be 2148 g. The mass of pycnometer full of clean water was 1932 g. Taking G = 2.65.What is the water content of the soil sample?a)1.95%b)2.75%c)3.25%d)6.50%Correct answer is option 'D'. Can you explain this answer?.
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