Introduction:
The probability of getting a head in a single coin toss is 1/2 since there are only two possible outcomes - heads or tails. In this problem, we are interested in finding the probability of getting a head three times out of eight coin tosses.

Approach:
To solve this problem, we can use the concept of binomial probability. The binomial distribution is used to calculate the probability of a specific number of successes in a fixed number of independent trials, where each trial has the same probability of success.

Step-by-step solution:
1. The probability of getting a head in a single coin toss is 1/2.
2. The probability of getting a tail in a single coin toss is also 1/2.
3. We need to find the probability of getting a head three times out of eight coin tosses.
4. We can use the binomial probability formula to calculate this probability:
P(x) = nCx * p^x * q^(n-x)
where P(x) is the probability of getting x successes in n trials,
nCx is the number of ways to choose x successes out of n trials (nCx = n! / (x! * (n-x)!)),
p is the probability of success in a single trial (getting a head in this case),
q is the probability of failure in a single trial (getting a tail in this case),
and x is the number of successes we are interested in (getting a head three times in this case).
5. Plugging in the values into the formula, we have:
P(3) = 8C3 * (1/2)^3 * (1/2)^(8-3)
P(3) = 8! / (3! * (8-3)!) * (1/2)^3 * (1/2)^(8-3)
P(3) = (8 * 7 * 6) / (3 * 2 * 1) * (1/8) * (1/2)^5
P(3) = 56 / 6 * 1/8 * 1/32
P(3) = 7/16 * 1/32
P(3) = 7/512
6. Therefore, the probability of getting a head three times out of eight coin tosses is 7/512.

Conclusion:
The probability of getting a head three times out of eight coin tosses is 7/512.