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An egg with a mass of 0.1 kg and specific heat of 3.32kj/kg c is dropped into a boiling water at 95c if the initial temperature of egg is 5c the maximum amount of the heat transfer to the egg is?
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An egg with a mass of 0.1 kg and specific heat of 3.32kj/kg c is dropp...
Calculation of Heat Transfer to the Egg

Given:
- Mass of egg = 0.1 kg
- Specific heat of egg = 3.32 kJ/kg°C
- Initial temperature of egg = 5°C
- Boiling water temperature = 95°C

Formula:
The heat transfer equation is Q = mcΔT, where
- Q = heat transferred (in Joules)
- m = mass of the egg (in kg)
- c = specific heat of the egg (in kJ/kg°C)
- ΔT = change in temperature (in °C)

Calculation:
The change in temperature of the egg is:
ΔT = final temperature - initial temperature
ΔT = 95°C - 5°C
ΔT = 90°C

The heat transferred to the egg is:
Q = mcΔT
Q = 0.1 kg x 3.32 kJ/kg°C x 90°C
Q = 29.88 kJ

Therefore, the maximum amount of heat transferred to the egg is 29.88 kJ.

Explanation:
When the egg is dropped into the boiling water, heat starts to transfer from the water to the egg. The heat transfer equation is used to calculate the amount of heat transferred to the egg. The specific heat of the egg is used to determine how much energy is required to raise the temperature of the egg by 1°C. The mass of the egg is used to determine how much heat is required to raise the temperature of the egg by a certain amount. Finally, the change in temperature is calculated by subtracting the initial temperature of the egg from the final temperature of the egg. The heat transferred to the egg is then calculated using the heat transfer equation.
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An egg with a mass of 0.1 kg and specific heat of 3.32kj/kg c is dropped into a boiling water at 95c if the initial temperature of egg is 5c the maximum amount of the heat transfer to the egg is?
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