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Three toys are in the shape of a cylinder, hemisphere, and cone. The three toys have the same base. The height of each toy is 2 √2. What is the ratio of the total surface areas of the cylinder, hemisphere, and cone, respectively?
  • a)
    4 : 3 : √2 +1
  • b)
    4 : 3 : 2 + √2
  • c)
    4 : 3 : 2 √2
  • d)
    2 : 1 : √2 + 1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Three toys are in the shape of a cylinder, hemisphere, and cone. The ...
Height of each toy =2√2 since the height of hemisphere = radius of the hemisphere
= radius of each toy =2√2 slant height of cone
ratio = T.S.A of cylinder : T.S.A of hemisphere : T.S.A of cone =2πr(h+r):3πr2:πr(l+r)
=2(h+r):3r:(l+r)
=2(4√2):3×2√2:(4+2√2)
= 4 : 3 : √2 + 1
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Three toys are in the shape of a cylinder, hemisphere, and cone. The three toys have the same base. The height of each toy is 2 √2. What is the ratio of the total surface areas of the cylinder, hemisphere, and cone, respectively?a)4 : 3 : √2 +1b)4 : 3 : 2 + √2c)4 : 3 : 2 √2d)2 : 1 : √2 + 1Correct answer is option 'A'. Can you explain this answer?
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