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For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0?
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For a potentiometric titration, in the curve of emf (E) vs volume (V) ...
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Equivalence point in a potentiometric titration is indicated by the condition where the amount of titrant added is stoichiometrically equal to the amount of analyte present in the solution. At this point, there is a sudden change in the emf of the system due to the completion of the reaction.
The curve of emf (E) vs volume (V) of the titrant added during potentiometric titration can be used to determine the equivalence point. The following conditions are used to identify the equivalence point in the curve:
|dE / dv| = 0:
This condition indicates the point of maximum slope in the curve. At this point, the rate of change of the emf with respect to the volume of titrant added is zero. This point is close to the equivalence point, but not exactly at it.
|d²E/dv²| > 0:
This condition indicates the inflection point in the curve. At this point, the rate of change of the slope of the curve with respect to the volume of titrant added is positive. This point is closer to the equivalence point than the point of maximum slope.
|d²E/dv²| = 0:
This condition indicates the exact equivalence point in the curve. At this point, the slope of the curve is at a maximum, and the rate of change of the slope of the curve with respect to the volume of titrant added is zero.
|dE / dv| > 0,|d²E/dv²| > 0:
This condition indicates that the equivalence point has been crossed. At this point, the rate of change of the emf with respect to the volume of titrant added is positive, and the rate of change of the slope of the curve with respect to the volume of titrant added is also positive.
In summary, the correct answer is (a) |dE / dv| = 0,|d²E/dv²| = 0, which indicates the exact equivalence point in the curve.
Equivalence point in a potentiometric titration is indicated by the condition where the amount of titrant added is stoichiometrically equal to the amount of analyte present in the solution. At this point, there is a sudden change in the emf of the system due to the completion of the reaction.
The curve of emf (E) vs volume (V) of the titrant added during potentiometric titration can be used to determine the equivalence point. The following conditions are used to identify the equivalence point in the curve:
|dE / dv| = 0:
This condition indicates the point of maximum slope in the curve. At this point, the rate of change of the emf with respect to the volume of titrant added is zero. This point is close to the equivalence point, but not exactly at it.
|d²E/dv²| > 0:
This condition indicates the inflection point in the curve. At this point, the rate of change of the slope of the curve with respect to the volume of titrant added is positive. This point is closer to the equivalence point than the point of maximum slope.
|d²E/dv²| = 0:
This condition indicates the exact equivalence point in the curve. At this point, the slope of the curve is at a maximum, and the rate of change of the slope of the curve with respect to the volume of titrant added is zero.
|dE / dv| > 0,|d²E/dv²| > 0:
This condition indicates that the equivalence point has been crossed. At this point, the rate of change of the emf with respect to the volume of titrant added is positive, and the rate of change of the slope of the curve with respect to the volume of titrant added is also positive.
In summary, the correct answer is (a) |dE / dv| = 0,|d²E/dv²| = 0, which indicates the exact equivalence point in the curve.
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For a potentiometric titration, in the curve of emf (E) vs volume (V) ...
Option b
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For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0?
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For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0?.
For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0?.
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For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0?, a detailed solution for For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? has been provided alongside types of For a potentiometric titration, in the curve of emf (E) vs volume (V) of the titrant added, the equivalence point is indicated by (a) |dE / dv| = 0,|d²E/dv²| = 0 (b) |dE/ dv| = 0,|d² E/dv²| > 0 (c) |dE / dv] > 0, |d²E/dv²| = 0 (d) |dE / dv| > 0,|d² E/dv²| > 0? theory, EduRev gives you an
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