Directions : In the following questions, A statement of Assertion (A)...
Given alternating voltage V = 4√2 sin 314t. Where peak value = V0 = 4√2 volt. VRMS = V0/√2 = 4 volt. Hence both assertion and reason both are true. But the reason does not properly explain the assertion.
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Directions : In the following questions, A statement of Assertion (A)...
Assertion (A): VRMS value of an alternating voltage V = 4√2 sin 314t is 4 volts.
Reason (R): Peak value of the alternating voltage is 4√2 volts.
To understand the given statement and reason, let's break down the terms and concepts involved:
Alternating Voltage:
An alternating voltage is a type of electrical voltage that changes its magnitude and direction over time. It is typically represented by a sinusoidal waveform.
VRMS:
VRMS (Root Mean Square Voltage) is a measure of the average voltage of an alternating voltage waveform. It is calculated by taking the square root of the mean of the squares of the instantaneous voltage values over one complete cycle.
Peak Value:
The peak value of an alternating voltage is the maximum value it reaches during one complete cycle.
Now, let's analyze the given statements:
Statement (A): VRMS value of an alternating voltage V = 4√2 sin 314t is 4 volts.
The given alternating voltage waveform is V = 4√2 sin 314t.
To find the VRMS value, we need to calculate the average voltage over one complete cycle. Since the waveform is a sine wave, the average value over one complete cycle is zero.
However, the VRMS value is calculated by taking the square root of the mean of the squares of the instantaneous voltage values. In this case, the instantaneous voltage values are positive and negative, resulting in a non-zero VRMS value.
To calculate the VRMS value, we can use the formula:
VRMS = (Vpeak) / √2
The peak value of the given waveform is 4√2 volts. Substituting this value in the formula, we get:
VRMS = (4√2) / √2
= 4 volts
Therefore, statement (A) is true.
Statement (R): Peak value of the alternating voltage is 4√2 volts.
The peak value of an alternating voltage is the maximum value it reaches during one complete cycle. In this case, the given waveform is V = 4√2 sin 314t.
The amplitude of a sine wave represents the peak value. In this case, the amplitude is 4√2. Therefore, the peak value of the waveform is 4√2 volts.
Therefore, statement (R) is true.
Conclusion:
Both statement (A) and statement (R) are true. Statement (R) is the correct explanation of statement (A) because the VRMS value is calculated using the peak value of the alternating voltage. In this case, the VRMS value is 4 volts, which is the correct explanation based on the peak value of 4√2 volts.